3.2439 \(\int \frac {(1-2 x)^{5/2} (2+3 x)}{(3+5 x)^{3/2}} \, dx\)

Optimal. Leaf size=116 \[ -\frac {2 (1-2 x)^{7/2}}{55 \sqrt {5 x+3}}+\frac {7}{275} \sqrt {5 x+3} (1-2 x)^{5/2}+\frac {7}{100} \sqrt {5 x+3} (1-2 x)^{3/2}+\frac {231 \sqrt {5 x+3} \sqrt {1-2 x}}{1000}+\frac {2541 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{1000 \sqrt {10}} \]

[Out]

2541/10000*arcsin(1/11*22^(1/2)*(3+5*x)^(1/2))*10^(1/2)-2/55*(1-2*x)^(7/2)/(3+5*x)^(1/2)+7/100*(1-2*x)^(3/2)*(
3+5*x)^(1/2)+7/275*(1-2*x)^(5/2)*(3+5*x)^(1/2)+231/1000*(1-2*x)^(1/2)*(3+5*x)^(1/2)

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Rubi [A]  time = 0.03, antiderivative size = 116, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {78, 50, 54, 216} \[ -\frac {2 (1-2 x)^{7/2}}{55 \sqrt {5 x+3}}+\frac {7}{275} \sqrt {5 x+3} (1-2 x)^{5/2}+\frac {7}{100} \sqrt {5 x+3} (1-2 x)^{3/2}+\frac {231 \sqrt {5 x+3} \sqrt {1-2 x}}{1000}+\frac {2541 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{1000 \sqrt {10}} \]

Antiderivative was successfully verified.

[In]

Int[((1 - 2*x)^(5/2)*(2 + 3*x))/(3 + 5*x)^(3/2),x]

[Out]

(-2*(1 - 2*x)^(7/2))/(55*Sqrt[3 + 5*x]) + (231*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/1000 + (7*(1 - 2*x)^(3/2)*Sqrt[3 +
5*x])/100 + (7*(1 - 2*x)^(5/2)*Sqrt[3 + 5*x])/275 + (2541*ArcSin[Sqrt[2/11]*Sqrt[3 + 5*x]])/(1000*Sqrt[10])

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 54

Int[1/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_.) + (d_.)*(x_)]), x_Symbol] :> Dist[2/Sqrt[b], Subst[Int[1/Sqrt[b*c -
a*d + d*x^2], x], x, Sqrt[a + b*x]], x] /; FreeQ[{a, b, c, d}, x] && GtQ[b*c - a*d, 0] && GtQ[b, 0]

Rule 78

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> -Simp[((b*e - a*f
)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(f*(p + 1)*(c*f - d*e)), x] - Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1)
+ c*f*(p + 1)))/(f*(p + 1)*(c*f - d*e)), Int[(c + d*x)^n*(e + f*x)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, f,
n}, x] && LtQ[p, -1] && ( !LtQ[n, -1] || IntegerQ[p] ||  !(IntegerQ[n] ||  !(EqQ[e, 0] ||  !(EqQ[c, 0] || LtQ
[p, n]))))

Rule 216

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[(Rt[-b, 2]*x)/Sqrt[a]]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rubi steps

\begin {align*} \int \frac {(1-2 x)^{5/2} (2+3 x)}{(3+5 x)^{3/2}} \, dx &=-\frac {2 (1-2 x)^{7/2}}{55 \sqrt {3+5 x}}+\frac {21}{55} \int \frac {(1-2 x)^{5/2}}{\sqrt {3+5 x}} \, dx\\ &=-\frac {2 (1-2 x)^{7/2}}{55 \sqrt {3+5 x}}+\frac {7}{275} (1-2 x)^{5/2} \sqrt {3+5 x}+\frac {7}{10} \int \frac {(1-2 x)^{3/2}}{\sqrt {3+5 x}} \, dx\\ &=-\frac {2 (1-2 x)^{7/2}}{55 \sqrt {3+5 x}}+\frac {7}{100} (1-2 x)^{3/2} \sqrt {3+5 x}+\frac {7}{275} (1-2 x)^{5/2} \sqrt {3+5 x}+\frac {231}{200} \int \frac {\sqrt {1-2 x}}{\sqrt {3+5 x}} \, dx\\ &=-\frac {2 (1-2 x)^{7/2}}{55 \sqrt {3+5 x}}+\frac {231 \sqrt {1-2 x} \sqrt {3+5 x}}{1000}+\frac {7}{100} (1-2 x)^{3/2} \sqrt {3+5 x}+\frac {7}{275} (1-2 x)^{5/2} \sqrt {3+5 x}+\frac {2541 \int \frac {1}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx}{2000}\\ &=-\frac {2 (1-2 x)^{7/2}}{55 \sqrt {3+5 x}}+\frac {231 \sqrt {1-2 x} \sqrt {3+5 x}}{1000}+\frac {7}{100} (1-2 x)^{3/2} \sqrt {3+5 x}+\frac {7}{275} (1-2 x)^{5/2} \sqrt {3+5 x}+\frac {2541 \operatorname {Subst}\left (\int \frac {1}{\sqrt {11-2 x^2}} \, dx,x,\sqrt {3+5 x}\right )}{1000 \sqrt {5}}\\ &=-\frac {2 (1-2 x)^{7/2}}{55 \sqrt {3+5 x}}+\frac {231 \sqrt {1-2 x} \sqrt {3+5 x}}{1000}+\frac {7}{100} (1-2 x)^{3/2} \sqrt {3+5 x}+\frac {7}{275} (1-2 x)^{5/2} \sqrt {3+5 x}+\frac {2541 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )}{1000 \sqrt {10}}\\ \end {align*}

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Mathematica [A]  time = 0.06, size = 83, normalized size = 0.72 \[ \frac {2541 \sqrt {5 x+3} \sqrt {20 x-10} \sinh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {2 x-1}\right )-10 \left (1600 x^4-3480 x^3+3590 x^2+761 x-943\right )}{10000 \sqrt {1-2 x} \sqrt {5 x+3}} \]

Antiderivative was successfully verified.

[In]

Integrate[((1 - 2*x)^(5/2)*(2 + 3*x))/(3 + 5*x)^(3/2),x]

[Out]

(-10*(-943 + 761*x + 3590*x^2 - 3480*x^3 + 1600*x^4) + 2541*Sqrt[3 + 5*x]*Sqrt[-10 + 20*x]*ArcSinh[Sqrt[5/11]*
Sqrt[-1 + 2*x]])/(10000*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])

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fricas [A]  time = 0.95, size = 86, normalized size = 0.74 \[ -\frac {2541 \, \sqrt {10} {\left (5 \, x + 3\right )} \arctan \left (\frac {\sqrt {10} {\left (20 \, x + 1\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{20 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) - 20 \, {\left (800 \, x^{3} - 1340 \, x^{2} + 1125 \, x + 943\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{20000 \, {\left (5 \, x + 3\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)*(2+3*x)/(3+5*x)^(3/2),x, algorithm="fricas")

[Out]

-1/20000*(2541*sqrt(10)*(5*x + 3)*arctan(1/20*sqrt(10)*(20*x + 1)*sqrt(5*x + 3)*sqrt(-2*x + 1)/(10*x^2 + x - 3
)) - 20*(800*x^3 - 1340*x^2 + 1125*x + 943)*sqrt(5*x + 3)*sqrt(-2*x + 1))/(5*x + 3)

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giac [A]  time = 1.77, size = 124, normalized size = 1.07 \[ \frac {1}{25000} \, {\left (4 \, {\left (8 \, \sqrt {5} {\left (5 \, x + 3\right )} - 139 \, \sqrt {5}\right )} {\left (5 \, x + 3\right )} + 3597 \, \sqrt {5}\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} + \frac {2541}{10000} \, \sqrt {10} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right ) - \frac {121 \, \sqrt {10} {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}}{6250 \, \sqrt {5 \, x + 3}} + \frac {242 \, \sqrt {10} \sqrt {5 \, x + 3}}{3125 \, {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)*(2+3*x)/(3+5*x)^(3/2),x, algorithm="giac")

[Out]

1/25000*(4*(8*sqrt(5)*(5*x + 3) - 139*sqrt(5))*(5*x + 3) + 3597*sqrt(5))*sqrt(5*x + 3)*sqrt(-10*x + 5) + 2541/
10000*sqrt(10)*arcsin(1/11*sqrt(22)*sqrt(5*x + 3)) - 121/6250*sqrt(10)*(sqrt(2)*sqrt(-10*x + 5) - sqrt(22))/sq
rt(5*x + 3) + 242/3125*sqrt(10)*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22))

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maple [A]  time = 0.01, size = 116, normalized size = 1.00 \[ \frac {\left (16000 \sqrt {-10 x^{2}-x +3}\, x^{3}-26800 \sqrt {-10 x^{2}-x +3}\, x^{2}+12705 \sqrt {10}\, x \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )+22500 \sqrt {-10 x^{2}-x +3}\, x +7623 \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )+18860 \sqrt {-10 x^{2}-x +3}\right ) \sqrt {-2 x +1}}{20000 \sqrt {-10 x^{2}-x +3}\, \sqrt {5 x +3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((-2*x+1)^(5/2)*(3*x+2)/(5*x+3)^(3/2),x)

[Out]

1/20000*(16000*(-10*x^2-x+3)^(1/2)*x^3+12705*10^(1/2)*x*arcsin(20/11*x+1/11)-26800*(-10*x^2-x+3)^(1/2)*x^2+762
3*10^(1/2)*arcsin(20/11*x+1/11)+22500*(-10*x^2-x+3)^(1/2)*x+18860*(-10*x^2-x+3)^(1/2))*(-2*x+1)^(1/2)/(-10*x^2
-x+3)^(1/2)/(5*x+3)^(1/2)

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maxima [A]  time = 1.51, size = 92, normalized size = 0.79 \[ -\frac {8 \, x^{4}}{5 \, \sqrt {-10 \, x^{2} - x + 3}} + \frac {87 \, x^{3}}{25 \, \sqrt {-10 \, x^{2} - x + 3}} - \frac {359 \, x^{2}}{100 \, \sqrt {-10 \, x^{2} - x + 3}} - \frac {2541}{20000} \, \sqrt {10} \arcsin \left (-\frac {20}{11} \, x - \frac {1}{11}\right ) - \frac {761 \, x}{1000 \, \sqrt {-10 \, x^{2} - x + 3}} + \frac {943}{1000 \, \sqrt {-10 \, x^{2} - x + 3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)*(2+3*x)/(3+5*x)^(3/2),x, algorithm="maxima")

[Out]

-8/5*x^4/sqrt(-10*x^2 - x + 3) + 87/25*x^3/sqrt(-10*x^2 - x + 3) - 359/100*x^2/sqrt(-10*x^2 - x + 3) - 2541/20
000*sqrt(10)*arcsin(-20/11*x - 1/11) - 761/1000*x/sqrt(-10*x^2 - x + 3) + 943/1000/sqrt(-10*x^2 - x + 3)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\left (1-2\,x\right )}^{5/2}\,\left (3\,x+2\right )}{{\left (5\,x+3\right )}^{3/2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((1 - 2*x)^(5/2)*(3*x + 2))/(5*x + 3)^(3/2),x)

[Out]

int(((1 - 2*x)^(5/2)*(3*x + 2))/(5*x + 3)^(3/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (1 - 2 x\right )^{\frac {5}{2}} \left (3 x + 2\right )}{\left (5 x + 3\right )^{\frac {3}{2}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)**(5/2)*(2+3*x)/(3+5*x)**(3/2),x)

[Out]

Integral((1 - 2*x)**(5/2)*(3*x + 2)/(5*x + 3)**(3/2), x)

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